Just remember Zx and Zy are tuples. Can I tell police to wait and call a lawyer when served with a search warrant? If you try your proposed code, it would give something like this: Person{name=Giant L2, age=100} Person{name=Derp L1, age=50} Person{name=John L2, age=50} Person{name=Menard L1, age=44} Person{name=Lili L1, age=44} Person{name=Lili L2, age=44} Person{name=Menard L2, age=44} Person{name=Bob L1, age=22} Person{name=Alec L1, age=21} Person{name=Herp L1, age=21} Person{name=Alec L2, age=21} Person{name=Herp L2, age=21} Person{name=Alice L1, age=12} Person{name=Little L2, age=5} And it's not what I'm looking for. If so, how close was it? 2. I mean swapItems(), removeItem(), addItem(), setItem() ?? 1. 3.1. I am also wandering if there is a better way to do that. How to remove an element from a list by index, Sorting an array of objects by property values, String formatting: % vs. .format vs. f-string literal. your map should be collected to a LinkedHashMap in order to preserve the order of listB. For example, the following code creates a list of Student and in-place . you can leverage that solution directly in your existing df. 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Output: Lets see another example where we will sort a list of custom objects. Guava has a ready-to-use comparator for doing that: Ordering.explicit(). Find the max recommended item from second sublist (3 to end of list) and add it to the newly created list and . IMO, you need to persist something else. Then you can create your custom Comparator that uses the Map to create an order: Then you can sort listA using your custom Comparator. 2023 ITCodar.com. 1. ', not 'How to sorting list based on values from another list?'. I am a bit confused with FactoryPriceComparator class. Browse other questions tagged, Where developers & technologists share private knowledge with coworkers, Reach developers & technologists worldwide. In which case this answer is somewhat valid, but just needs to be the intersection of sets (remove missing elements). It returns a comparator that imposes reverse of the natural ordering. Once we have the list of values in a sorted manner, we build the HashMap again based on this new list. This comparator sorts the list of values alphabetically. For cases like these, we'll want to write a custom Comparator: And now, when we execute this code, we've got the natural order of names, as well as ages, sorted: Here, we've used a Lambda expression to create a new Comparator implicitly and defined the logic for sorting/comparison. - Hatefiend Any suggestions? In addition, the proposed solution won't work for the initial question as the lists X and Y contain different entries. The naive implementation that brute force searches listB would not be the best performance-wise, but would be functionally sufficient. good solution! "Sunday" => 0, , "Saturday" => 6. Your compare methods are currently doing: This can be written more concisely with the built-in Double.compare (since Java 7), which also properly handles NaN, -0.0 and 0.0, contrary to your current code: Note that you would have the same implementation for the Comparator. As you can see that we are using Collections.sort() method to sort the list of Strings. Returning a positive number indicates that an element is greater than another. How can this new ban on drag possibly be considered constitutional? Does this require that the values in X are unqiue? If they are already numpy arrays, then it's simply. As for won't work..that's right because he posted the wrong question in the title when he talked about lists. Lets take an example where value is a class called Name. zip, sort by the second column, return the first column. Oh, ignore, I can do sorted(zip(Index,X,Y,Z)) too. What happens if you have in List1, 50, 40 30 , and in List2 50 45 42? If you have 2 lists of identical number of items and where every item in list 1 is related to list 2 in the same order (e.g a = 0 , b = 1, etc.) Wed like to help. Can airtags be tracked from an iMac desktop, with no iPhone? Disconnect between goals and daily tasksIs it me, or the industry? Whats the grammar of "For those whose stories they are"? The best answers are voted up and rise to the top, Not the answer you're looking for? We first get the String values in a list. If values in the HashMap are of type Integer, the code will be as follows : Here HashMap values are sorted according to Integer values. How can I pair socks from a pile efficiently? How can we prove that the supernatural or paranormal doesn't exist? Your problem statement is not very clear. Can you write oxidation states with negative Roman numerals? All rights reserved. @Jack Yes, like what I did in the last example. We can use this by creating a list of Integers and sort these using the Collections.sort(). The answer of riza might be useful when plotting data, since zip(*sorted(zip(X, Y), key=lambda pair: pair[0])) returns both the sorted X and Y sorted with values of X. By clicking Accept all cookies, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy. The basic strategy is to get the values from the HashMap in a list and sort the list. @RichieV I recommend using Quicksort or an in-place merge sort implementation. Zip the two lists together, sort it, then take the parts you want: Also, if you don't mind using numpy arrays (or in fact already are dealing with numpy arrays), here is another nice solution: I found it here: When we compare null, it throws NullPointerException. I don't know if it is only me, but doing : Please add some more context to your post. I have two lists List list1 = new ArrayList(), list2 = new ArrayList(); (Not the same size), of the class Person: I want to create a new list using list1 and list2 sorted by age (descending), but I also another condition that is better explained with an example: He should, because his age is equal to Menard, Alec is from L1 and two Person from L1 can't be one after another is this kind of situation happens. 2. In Python 2, zip produced a list. It is stable for an ordered stream. By clicking Accept all cookies, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy.

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